java.util.concurrent.ForkJoinPool Example

The combination of RecursiveTask implementations running in a ForkJoinPool allows tasks to be defined that may spawn subtasks that in turn may run asynchronously. The ForkJoinPool manages efficient processing of those tasks.

This article presents a simple calculator application to evaluate a formula defined as a List presents a single-threaded recursive solution, and then converts that solution to use RecursiveTasks executed in a ForkJoinPool.

Recursive Solution

A formula to be computed is defined as follows:

    public enum Operator { ADD, MULTIPLY; }

    public static List<?> FORMULA =
        List.of(Operator.ADD,
                List.of(Operator.MULTIPLY, 1, 2, 3), 4, 5,
                List.of(Operator.ADD, 6, 7, 8,
                        List.of(Operator.MULTIPLY, 9, 10, 11)));

A formula is either a Number or a List consisting of an Operator followed by other formulae. For illustration, the Lisp equivalent of FORMULA would be:

(+ (* 1 2 3) 4 5
   (+ 6 7 8
      (* 9 10 11)))

A Task class is defined to solve formulae:

    public static class Task {
        private final Object formula;

        public Task(Object formula) { this.formula = formula; }

        public Integer compute() {
            Integer result = null;

            if (formula instanceof Number) {
                result = ((Number) formula).intValue();
            } else {
                List<?> list = (List<?>) formula;
                Operator operator = (Operator) list.get(0);
                List<Task> subtasks =
                    list.subList(1, list.size())
                    .stream()
                    .map(Task::new)
                    .collect(toList());
                IntStream operands =
                    subtasks.stream()
                    .map(Task::compute)
                    .mapToInt(Integer::intValue);

                switch (operator) {
                case ADD:
                    result = operands.sum();
                    break;

                case MULTIPLY:
                    result = operands.reduce(1, (x, y) -> x * y);
                    break;
                }
            }

            System.out.println(formula + " -> " + result);

            return result;
        }
    }

The compute() method evaluates the formula by creating another Task instance to evaluate each operand recursively by calling compute(). The actual mechanics are to create a List of Tasks and then map the Stream of Tasks to an IntStream by calling Task.compute() which is evaluated based on the operator.

The static main(String[]) function simply instantiates a Task and calls compute().

    public static void main(String[] argv) {
        Task task = new Task(FORMULA);

        System.out.println("Result: " + task.compute());
    }

Which generates the following output:

1 -> 1
2 -> 2
3 -> 3
[MULTIPLY, 1, 2, 3] -> 6
4 -> 4
5 -> 5
6 -> 6
7 -> 7
8 -> 8
9 -> 9
10 -> 10
11 -> 11
[MULTIPLY, 9, 10, 11] -> 990
[ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]] -> 1011
[ADD, [MULTIPLY, 1, 2, 3], 4, 5, [ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]]] -> 1026
Result: 1026

The next chapter details how to convert this solution to use ForkJoinPool to enable some level of parallel processing.

ForkJoinPool Solution

The Task class is modified to extend RecursiveTask<Integer>. When a subtask is instantiated, RecursiveTask.fork() is called to asynchronously execute this task in the pool the current task is running in. In the IntStream, RecursiveTask.join() is called to wait for the subtask to complete (if it hasn’t already) and return the result of the compute() method.

    public static class Task extends RecursiveTask<Integer> {
        ...
        @Override
        public Integer compute() {
            Integer result = null;

            if (formula instanceof Number) {
                ...
            } else {
                ...
                List<Task> subtasks =
                    list.subList(1, list.size())
                    .stream()
                    .map(Task::new)
                    .peek(RecursiveTask::fork)
                    .collect(toList());
                IntStream operands =
                    subtasks.stream()
                    .map(RecursiveTask::join)
                    .mapToInt(Integer::intValue);
                ...
            }

            System.out.println(Thread.currentThread() + "\t"
                               + formula + " -> " + result);

            return result;
        }
    }

The executing Thread is included in the output to demonstrate the behavior. The main(String[]) function creates a ForkJoinPool, the Task to compute FORMULA, and uses the pool to invoke the Task. The result is obtained through Task.join() to wait for the computation to complete.

    public static int N = 10;

    public static void main(String[] argv) {
        ForkJoinPool pool = new ForkJoinPool(N);
        RecursiveTask<Integer> task = new Task(FORMULA);

        pool.invoke(task);

        System.out.println("Result: " + task.join());
    }

Output using 10 threads (N = 10):

Thread[ForkJoinPool-1-worker-31,5,main]	2 -> 2
Thread[ForkJoinPool-1-worker-19,5,main]	8 -> 8
Thread[ForkJoinPool-1-worker-23,5,main]	4 -> 4
Thread[ForkJoinPool-1-worker-17,5,main]	3 -> 3
Thread[ForkJoinPool-1-worker-9,5,main]	1 -> 1
Thread[ForkJoinPool-1-worker-27,5,main]	5 -> 5
Thread[ForkJoinPool-1-worker-3,5,main]	7 -> 7
Thread[ForkJoinPool-1-worker-21,5,main]	6 -> 6
Thread[ForkJoinPool-1-worker-17,5,main]	11 -> 11
Thread[ForkJoinPool-1-worker-23,5,main]	10 -> 10
Thread[ForkJoinPool-1-worker-31,5,main]	9 -> 9
Thread[ForkJoinPool-1-worker-5,5,main]	[MULTIPLY, 1, 2, 3] -> 6
Thread[ForkJoinPool-1-worker-31,5,main]	[MULTIPLY, 9, 10, 11] -> 990
Thread[ForkJoinPool-1-worker-13,5,main]	[ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]] -> 1011
Thread[ForkJoinPool-1-worker-19,5,main]	[ADD, [MULTIPLY, 1, 2, 3], 4, 5, [ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]]] -> 1026
Result: 1026

And with 1 pool thread (N = 1):

Thread[ForkJoinPool-1-worker-3,5,main]	1 -> 1
Thread[ForkJoinPool-1-worker-3,5,main]	2 -> 2
Thread[ForkJoinPool-1-worker-3,5,main]	3 -> 3
Thread[ForkJoinPool-1-worker-3,5,main]	[MULTIPLY, 1, 2, 3] -> 6
Thread[ForkJoinPool-1-worker-3,5,main]	4 -> 4
Thread[ForkJoinPool-1-worker-3,5,main]	5 -> 5
Thread[ForkJoinPool-1-worker-3,5,main]	6 -> 6
Thread[ForkJoinPool-1-worker-3,5,main]	7 -> 7
Thread[ForkJoinPool-1-worker-3,5,main]	8 -> 8
Thread[ForkJoinPool-1-worker-3,5,main]	9 -> 9
Thread[ForkJoinPool-1-worker-3,5,main]	10 -> 10
Thread[ForkJoinPool-1-worker-3,5,main]	11 -> 11
Thread[ForkJoinPool-1-worker-3,5,main]	[MULTIPLY, 9, 10, 11] -> 990
Thread[ForkJoinPool-1-worker-3,5,main]	[ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]] -> 1011
Thread[ForkJoinPool-1-worker-3,5,main]	[ADD, [MULTIPLY, 1, 2, 3], 4, 5, [ADD, 6, 7, 8, [MULTIPLY, 9, 10, 11]]] -> 1026
Result: 1026

Which (unsurprisingly) calculates the formulae in the same order as the recursive solution.

Summary

Single threaded recursive solutions may be converted to RecursiveTask1 implementations and invoked through a ForkJoinPool to enable efficient processing of subtasks.

[1] Implementation class of ForkJoinTask.